Calculating Mole Fractions and Attenuation Coefficients
Example 1: Water (in book):
- H2: n1 = 2, m1 = 1; O: n2 = 1, m2 = 16
- Q = (Si ni mi)-1= (2*1 + 1 * 16)-1 = 1/18
- Thus fH2 = 2/18, fO = 16/18,
- (s/r)Tot = Sifmi(s/r)I = (2/18)*(0.1129cm2g-1) + (16/18)(0.0570 cm2g -1)= 0.0632
Benzene (C6H6):
- C6: n1 = 6, m1 = 12; H6: n2 = 6, m2 = 1
- Q = (6*12+6*1) = 1/78, fC6 = 72/78, fH6 = 6/78